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Oracle Database SQL Sample Questions (Q39-Q44):
NEW QUESTION # 39
View the Exhibit and examine the structure of the SALESand PRODUCTStables. (Choose two.)
In the SALEStable, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOINoperator:
Which two JOINoperations can be used to obtain the required output? (Choose two.)
- A. JOIN
- B. FULL OUTER JOIN
- C. LEFT OUTER JOIN
- D. RIGHT OUTER JOIN
Answer: B,C
NEW QUESTION # 40
Examine the description products table:
Examine the description of the new_projects table;
Which two queries execute successfully?
- A.
- B.
- C.
- D.
- E.
Answer: B,C
Explanation:
To determine which queries will execute successfully, we need to consider the compatibility of the column definitions and the structure of the SELECT statements:
Option A uses the MINUS set operator, which subtracts rows returned by the second SELECT statement from the rows returned by the first. For MINUS to work, the number and the order of columns and their data types must be the same in both queries. This query will not execute successfully because the second SELECT statement does not include all columns from the first SELECT statement, and the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
Option B uses the UNION ALL set operator, which appends the results of the second SELECT statement to the results of the first. Unlike UNION, UNION ALL does not eliminate duplicate rows. This query will execute successfully because UNION ALL does not require the same data types or sizes, and the result will contain all columns from the first SELECT statement filled with NULL for non-matching columns from the second SELECT statement.
Option C uses the UNION set operator, which requires the same number of columns and compatible data types. This query will not execute successfully because PROD_NAME has different data types (CHAR(4) vs VARCHAR2(10)), and the result of a UNION must have the same number of columns with compatible data types in the two SELECT statements.
Option D uses the UNION set operator as well, but unlike Option C, it does not require a specific data type match because both SELECT statements include all columns and UNION is used (which will automatically handle type conversion where necessary). This query will execute successfully.
Option E uses the INTERSECT set operator, which requires the same number and order of columns and their data types to be identical or compatible. This query will not execute successfully because the data types and sizes of PROD_ID do not match (CHAR(2) vs CHAR(4)).
Reference:
Oracle Documentation on Set Operators: SQL Language Reference - Set Operators Oracle Documentation on Data Type Precedence: SQL Language Reference - Data Type Precedence In conclusion, only Option B and Option D will execute successfully because they adhere to the rules of the UNION ALL and UNION operators respectively, regarding column count and data type compatibility.
NEW QUESTION # 41
Evaluate the following ALTER TABLE statement:
ALTER TABLE orders
SET UNUSED (order_date);
Which statement is true?
- A. The DESCRIBE command would still display the ORDER_DATE column.
- B. ROLLBACK can be used to restore the ORDER_DATE column.
- C. After executing the ALTER TABLE command, a new column called ORDER_DATE can be added to the ORDERS table.
- D. The ORDER_DATE column must be empty for the ALTER TABLE command to execute successfully.
Answer: C
NEW QUESTION # 42
Examine the structure of the EMPLOYEES table. (Choose the best answer.)
You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
- A. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id
(SELECT employee_id FROM employees WHERE employee_id = 100)UNION
ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date >
SYSDATE -180INTERSECTSELECT last_name, hire_date, salaryFROM
employeesWHERE salary > 10000); - B. SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALL SELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id
100)INETRSECTSELECT last_name, hire_date, salaryFROM employees WHERE
hire_date > SYSDATE- 180; - C. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id
(SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -
1 80INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary >
1 0000; - D. (SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -180;
Answer: C
NEW QUESTION # 43
Examine these statements:
CREATE TABLE dept (
deptno NUMBER PRIMARY KEY,
diname VARCHAR2(10) ,
mgr NUMBER ,
CONSTRAINT dept_fkey FOREIGN KEY(mgr) REFERENCES emp (empno));
CREATE TABLE emp (
Empno NUMBER PRIMARY KEY,
Ename VARCHAR2 (10) ,
deptno NUMBER,
CONSTRAINT emp_fkey FOREIGN KEY (deptno) REFERENCES dept (deptno) DISABLE); ALTER TABLE emp MODIFY CONSTRAINT emp_fkey ENABLE; Which two are true?
- A. The Deptno column in the emp table will be able to contain nulls values.
- B. The CREATE TABLE EMP statement must precede the CREATE TABLE DEPT statement for all threestatements to execute successfully.
- C. The MGR column in the DEPT table will not be able to contain NULL values.
- D. The DEFT FKEY constraint definition must be removed from the CREATE TABLE DEF statement.and be added with an AITER TABLE statement once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.
- E. Both foreign key constraint definitions must be removed from the CREATE TABLE statements, andbe added with ALTER TABLE statements once both tables are created, for the two CREATE TABLEstatements to execute successfully in the order shown.
- F. All three statements execute successfully in the order shown
Answer: A,F
Explanation:
E). True. The deptno column in the emp table can contain null values unless explicitly constrained not to, which is not the case here.
F). True. The three statements can execute successfully in the order shown. The foreign key constraint in the dept table is referring to the emp table which does not yet exist, but this is not a problem because it is not immediately enabled. The emp table is created next with a disabled foreign key constraint referencing the already created dept table. Finally, the foreign key constraint on emp is enabled after both tables are in place.
A is incorrect because the MGR column can contain NULL values as there is no NOT NULL constraint applied to it. B is incorrect because the CREATE TABLE EMP statement contains a disabled foreign key, so it can be created before CREATE TABLE DEPT. C and D are incorrect because foreign key constraints do not need to be removed and added later for the tables to be created successfully; they can be managed as shown in the provided statements.
NEW QUESTION # 44
......
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